(s^2)+(2s)+5=0

Solution for (s^2)+(2s)+5=0 equation:

Simplifying
(s2) + (2s) + 5 = 0
s2 + (2s) + 5 = 0

Reorder the terms:
5 + (2s) + s2 = 0

Solving
5 + (2s) + s2 = 0

Solving for variable 's'.

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + (2s) + -5 + s2 = 0 + -5

Reorder the terms:
5 + -5 + (2s) + s2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + (2s) + s2 = 0 + -5
(2s) + s2 = 0 + -5

Combine like terms: 0 + -5 = -5
(2s) + s2 = -5

The s term is (2s).  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
(2s) + 1 + s2 = -5 + 1

Reorder the terms:
1 + (2s) + s2 = -5 + 1

Combine like terms: -5 + 1 = -4
1 + (2s) + s2 = -4

Factor a perfect square on the left side:
(s + 1)(s + 1) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.